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5^x-1/5^x=6
We move all terms to the left:
5^x-1/5^x-(6)=0
Domain of the equation: 5^x!=0We multiply all the terms by the denominator
x!=0/1
x!=0
x∈R
5^x*5^x-6*5^x-1=0
Wy multiply elements
25x^2-30x-1=0
a = 25; b = -30; c = -1;
Δ = b2-4ac
Δ = -302-4·25·(-1)
Δ = 1000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1000}=\sqrt{100*10}=\sqrt{100}*\sqrt{10}=10\sqrt{10}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-10\sqrt{10}}{2*25}=\frac{30-10\sqrt{10}}{50} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+10\sqrt{10}}{2*25}=\frac{30+10\sqrt{10}}{50} $
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